viernes, 27 de mayo de 2011
martes, 10 de mayo de 2011
jueves, 28 de abril de 2011
jueves, 14 de abril de 2011
Pruebas Enlace 2009 y 2010
ENLACE 2010:
Presiona aquí para ir a la prueba ENLACE en línea.
ENLACE 2009:
Prueba en Línea Enlace.
Haz las pruebas en línea y revisa tus resultados al finalizarlas.
Presiona aquí para ir a la prueba ENLACE en línea.
ENLACE 2009:
Prueba en Línea Enlace.
Haz las pruebas en línea y revisa tus resultados al finalizarlas.
miércoles, 13 de abril de 2011
lunes, 28 de marzo de 2011
sábado, 26 de marzo de 2011
Answers for 4th Period Review.
FOR THE PERIOD EXAM, DON´T FORGET:
- Compass
- Protractor
- Ruler
- Pencil
- Eraser
- Compass
- Protractor
- Ruler
- Pencil
- Eraser
Answers for 4th period exam (review)
View more documents from Dulce Garza.
viernes, 25 de marzo de 2011
jueves, 24 de marzo de 2011
Math Review for 4th Period Exam
Math review for 4th period exam
View more documents from Dulce Garza.
viernes, 18 de marzo de 2011
Percent Homework.
COPY ON YOUR NOTEBOOK
I. Solve the following percent problems.
A. The original price was $160, and Ned got a 20% discount? How much was the discount?
B. The original price was $90, and Ned got a $36 discount. How many percent off was the discount?
C. Ned's discount was 20% off the original price, which meant a $40 discount. What was the original price?
II. Enter to this link and solve the percent problems (on your notebook, show complete process)
Practice solving percents.
I. Solve the following percent problems.
A. The original price was $160, and Ned got a 20% discount? How much was the discount?
B. The original price was $90, and Ned got a $36 discount. How many percent off was the discount?
C. Ned's discount was 20% off the original price, which meant a $40 discount. What was the original price?
II. Enter to this link and solve the percent problems (on your notebook, show complete process)
Practice solving percents.
miércoles, 16 de marzo de 2011
lunes, 14 de marzo de 2011
viernes, 11 de marzo de 2011
jueves, 10 de marzo de 2011
viernes, 4 de marzo de 2011
Frecuencia Absoluta y Frecuencia Relativa
Frecuencia relativa y frecuencia absoluta.
View more presentations from Dulce Garza.
lunes, 28 de febrero de 2011
viernes, 25 de febrero de 2011
Construcción de Triángulos
To know if it is possible to construct a triangle, it is necessary to add any of the measures of two of its sides, and if the sum is greater than the third side, then it is possible.
Example 1:
Is it possible to construct a triangle which sides measure 8, 2, and 5 cm;
even though:
8 + 2 > 5 and 8 + 5 > 2 ; but, as: 2 + 5 <>
it is not possible to construct a triangle with these measurements.
Example 2:
Is it possible to construct a triangle which sides measure 6, 4, and 7cm;
6 + 4 > 7 and 6 + 7 > 4 and 7 + 4 > 6
It is possible!
miércoles, 23 de febrero de 2011
viernes, 18 de febrero de 2011
miércoles, 9 de febrero de 2011
domingo, 6 de febrero de 2011
Answers for Math 3rd Period Review
Answers for practice for third period exam 2011
View more documents from Dulce Garza.
viernes, 4 de febrero de 2011
miércoles, 2 de febrero de 2011
jueves, 27 de enero de 2011
Word Problems in Algebra.
WORD PROBLEMS fall into distinct types. Below are examples. The only difficulty will be translating verbal language into algebraic language.
Example 1. ax ± b = c. All problems like the following, lead eventually to an equation in that simple form.
Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse. How much was the blouse?
Solution. Every word problem has an unknown number. In this problem, it is the price of the blouse. Always let x represent the unknown number. That is, let x answer the question.
Let x, then, be how much she spent for the blouse. The problem states that "This" -- that is, $42 -- was $14 less than two times x. Here is the equation:
2x − 14 = 42.
2x = 42 + 14
2x = 56.
x = 56/2
x = 28
The blouse cost $28.
Click here to check more examples on WORD PROBLEMS IN ALGEBRA.
Example 1. ax ± b = c. All problems like the following, lead eventually to an equation in that simple form.
Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse. How much was the blouse?
Solution. Every word problem has an unknown number. In this problem, it is the price of the blouse. Always let x represent the unknown number. That is, let x answer the question.
Let x, then, be how much she spent for the blouse. The problem states that "This" -- that is, $42 -- was $14 less than two times x. Here is the equation:
2x − 14 = 42.
2x = 42 + 14
2x = 56.
x = 56/2
x = 28
The blouse cost $28.
Click here to check more examples on WORD PROBLEMS IN ALGEBRA.
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